5x^2-32/3=4x

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Solution for 5x^2-32/3=4x equation: 


x in (-oo:+oo)

5*x^2-(32/3) = 4*x // - 4*x

5*x^2-(4*x)-(32/3) = 0

5*x^2-4*x-32/3 = 0

5*x^2-4*x-32/3 = 0

DELTA = (-4)^2-(-32/3*4*5)

DELTA = 688/3

DELTA > 0

x = ((688/3)^(1/2)+4)/(2*5) or x = (4-(688/3)^(1/2))/(2*5)

x = ((688/3)^(1/2)+4)/10 or x = (4-(688/3)^(1/2))/10

x in { (4-(688/3)^(1/2))/10, ((688/3)^(1/2)+4)/10 }

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